The NBA announced the finalists for the 2025-26 Twyman-Stokes Teammate of the Year Award on Tuesday. Current NBA players will select the winner from these 12 finalists (six finalists from each NBA conference).
https://twitter.com/NBA/status/2039026761355157686
The players selected as finalists are below (listed alphabetically by last name):
- Desmond Bane, Orlando Magic
- Jalen Brunson, New York Knicks
- Pat Connaughton, Charlotte Hornets
- De’Aaron Fox, San Antonio Spurs
- Jeff Green, Houston Rockets
- Jrue Holiday, Portland Trail Blazers
- DeAndre Jordan, New Orleans Pelicans
- Duncan Robinson, Detroit Pistons
- Marcus Smart, Los Angeles Lakers
- Jayson Tatum, Boston Celtics
- Garrett Temple, Toronto Raptors
- Jaylin Williams, Oklahoma City Thunder
Stephen Curry of the Golden State Warriors won the award in 2024-25.
The annual honor recognizes the player deemed the best teammate based on selfless play, on and off the court leadership as a mentor and role model to other NBA players, and commitment and dedication to their team.
